I want to make sure I am properly understanding and applying Kirchoff's voltage law (the one where the voltages in the circuit add to 0V).
Suppose I have a picaxe and an n-MOSFET as depicted in the picaxe manual 3 (pin to gate, V+ to load to drain, source to ground/0V). Now suppose my MOSFET's datasheet says 20V in the Absolute Maximum Ratings (I grabbed this datasheet from digikey: http://www.vishay.com/docs/72322/72322.pdf).
Let V+ = 40V, Load = 10 x series Green LEDs (3.6Vf each) with an appropriate resistor. Is my MOSFET OK? Here's my work:
10 x 3.6V = 36V dropped in the series LEDs.
The MOSFET datasheet lists a "diode forward voltage"/Vsd of 0.8V (not too sure about this part).
I put a 3.2V / 20ma = 160Ohm (and 0.02^2 x 160 = 0.064...1/8W) resistor in series with the LEDs to drop the remaining voltage.
Thus I have 40V going in and 36 + 0.8 + 3.2 = 40V coming out. So Kirchoff seems happy. But my MOSFET is rated at 20V. So another way for me to ask that question is, when the MOSFET (or any part, I suppose) says "20V" as its limit, is that the gross voltage from my power supply or the net voltage after the load drops most of those volts? Does my 40V supply in the example kill the MOSFET? Or is the MOSFET safe (as long as the LEDs and resistor don't fail, obviously) after the 36V are dropped in the LEDs?
Assume a linear regulator to give only 5V to the picaxe.
Many thanks,
Suppose I have a picaxe and an n-MOSFET as depicted in the picaxe manual 3 (pin to gate, V+ to load to drain, source to ground/0V). Now suppose my MOSFET's datasheet says 20V in the Absolute Maximum Ratings (I grabbed this datasheet from digikey: http://www.vishay.com/docs/72322/72322.pdf).
Let V+ = 40V, Load = 10 x series Green LEDs (3.6Vf each) with an appropriate resistor. Is my MOSFET OK? Here's my work:
10 x 3.6V = 36V dropped in the series LEDs.
The MOSFET datasheet lists a "diode forward voltage"/Vsd of 0.8V (not too sure about this part).
I put a 3.2V / 20ma = 160Ohm (and 0.02^2 x 160 = 0.064...1/8W) resistor in series with the LEDs to drop the remaining voltage.
Thus I have 40V going in and 36 + 0.8 + 3.2 = 40V coming out. So Kirchoff seems happy. But my MOSFET is rated at 20V. So another way for me to ask that question is, when the MOSFET (or any part, I suppose) says "20V" as its limit, is that the gross voltage from my power supply or the net voltage after the load drops most of those volts? Does my 40V supply in the example kill the MOSFET? Or is the MOSFET safe (as long as the LEDs and resistor don't fail, obviously) after the 36V are dropped in the LEDs?
Assume a linear regulator to give only 5V to the picaxe.
Many thanks,