donrecardo
Senior Member
I know its a daft question , but I just dont know the answer
I could find it out by connecting it up and measuring but I hoped a quick yes or no answer from one of you would save me the effort.
I have built a large (5" gauge) model train . Its battery powered through 4 large motors and runs off 24v.
I have my two 12v batteries in series to give the 24v required and now I want to fit a digital ammeter which I already have so I can know how much current the motors are drawing.
The simple answer would be stick the meter shunt in the main battery positive or negative lead , but there is not a lot of space to fit it in there , however there is room to fit it in the lead that joins the two batteries together .
I have made a picture to show what I mean , lets see if I can find out how to attach a picture ......
http://donrecardo.pwp.blueyonder.co.uk/3.jpg
I am assumming that no matter if I fit the ammeter in the red, black or green lead the current will read the same as I assume its the same all around that part of the circuit but could someone please confirm if I am right or not please
Regards
Don
I could find it out by connecting it up and measuring but I hoped a quick yes or no answer from one of you would save me the effort.
I have built a large (5" gauge) model train . Its battery powered through 4 large motors and runs off 24v.
I have my two 12v batteries in series to give the 24v required and now I want to fit a digital ammeter which I already have so I can know how much current the motors are drawing.
The simple answer would be stick the meter shunt in the main battery positive or negative lead , but there is not a lot of space to fit it in there , however there is room to fit it in the lead that joins the two batteries together .
I have made a picture to show what I mean , lets see if I can find out how to attach a picture ......
http://donrecardo.pwp.blueyonder.co.uk/3.jpg
I am assumming that no matter if I fit the ammeter in the red, black or green lead the current will read the same as I assume its the same all around that part of the circuit but could someone please confirm if I am right or not please
Regards
Don
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